1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | #include <iostream> #include <math.h> using namespace std; int main () { int a,b,c,d,i,j,minimum; cout<<"Enter the all four number "; cin>>a>>b>>c>>d; if(a<b&&a<c&&a<d) minimum=a; else if (b<c&&b<d) minimum=b; else if (c<d) minimum=c; else minimum=d; for(j=minimum;;--j) { if(a%j==0 && b%j==0 && c%j==0&& d%j==0) { break; } } for(i=1;;i++) { if(i%a==0 && i%b==0 &&i%c==0&& i%d==0) break; } cout<<"Lowest Common factor=>"<<i<<endl; cout<<"Highest Common Factor="<<j; } |
import requests import urllib.request import time from bs4 import BeautifulSoup as bs import re url = ' https://en.wikipedia.org/wiki/Mobile_telephone_numbering_in_India' state_to_extract = "UE" #if set to None all state is considered telecom_to_extracted = None #if set to none all operator from particular city is extracted response = requests . get(url) print (response) soup = bs(response . text, "html.parser" ) one_a_tag = soup . findAll( 'tr' )[ 35 :] lst = [] for k in one_a_tag: s = k . findAll( 'td' ) limit = len (s) i = 0 while True : if i == limit: break no = s[i] . text i += 1 if i == limit: break operator = s[i] . text i += 1 if i == limit: break state = s[i] . text i += 1 if i == limit: break res = f "{no} {operator} {state}" if state_to_extract is None : if telecom_to_extracted is None : lst . append(no) elif telecom_to_e...
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