python program get union of two list (program to get A union B ) list method .

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#!/usr/bin/env python3 # -*- coding: utf-8 -*- """ Created on Fri Mar 16 17:08:52 2018 @author: beast """ def version1(): a=['a','b','c','d','e'] # list 1 b=['a','b','c','d','e','f','g','h'] # list 2 c=[k for k in (a)if (k in (a) and k not in (b))] # include unique item from list 1 : items are (list1-list2)(set thoery) d=[l for l in (b) if l in (a ) and l in (b) or (l not in (a) and l in (b))] #include all the comman from list 1 and unique from list 2 lst=c+d # append above two comprehensed list to get union of list1 U list2 lst.sort() # not neccessay but makes list easy to understand (sorting in ascending order ) print("\n\na=",a) print("\n\nb=",b) print("\n\nunion=",lst) return lst # make it easy to import and use e.g import union_beast.py and then call union_beast.version1() it will return this union of list def version2(): a=['a','b','c','d','e'] # list 1 b=['d','e','f','g','h'] # list 2 c=[] for k in range (max(len(a),len(b))):# max return maximum number among two or more number so we iterate over max of length of both the list if k <len(a) and a[k] not in (b) : # if length of a is greater than current indexing and element at kth index is not present in list b (ie get List1-list 2 item) c.append(a[k]) # if item is unique to list 1 then append to result list (here c) if k <len(b) and b[k] not in (a) :# same as above logic but here we get item unique to list 2 (here list b) c.append(b[k]) # same append to result list (here c) if k <len(b) and b[k] in (a) : # now add the comman item to list (this is vital step as we only add only one instance of item that are both present in list 1 and list 2) eg if 2 is present in list 1 and list 2 we add only one 2 to result list c.append(b[k]) # append to result list (here c) c.sort() # not neccessary but make the result more eye catchy print("\n\na=",a) #print list 1 print("\n\nb=",b)#print list 2 print("\n\nunion=",c) #print the result if __name__=="__main__": # used to run the function via main loading ...i.e if the module is not imported print("\n----------by version 1------------\n") version1() print("\n\n------------by version 2------------") version2()

NOTE: you can use [list].append([item]) function to take user input to list and then get the union operator