C AND C++ program to find out a pattern within a String

This program takes an input string From user and tell if the given string is present in the String or not

Example: This is always true

pattern-> is 

output -> pattern found 

and if pattern input -> zxc

output -> No match found 

NOTE: CODE:: BLOCKS IS USED in editing and compiling the source code ....

+++++++++++++++++++++++++++++C Source Code ++++++++++++++++++++++++++++++

#include <stdio.h>

#include <conio.h>

void main ()

{

char str[999],pattern[999];

int flag=0,i,j=0,loc;

printf("Enter the string \n");

gets(str);

printf("Enter the string to find pattern\n");

gets(pattern);

for(i=0;str[i]!='\0';i++)

{ /// main for loop

    if(flag==1) break;

    if(str[i]==pattern[0])

    {/// a match is found

        i++;

        flag=1;

loc=i;

        for( j=1;pattern[j]!='\0';j++)

        {

            if(str[i]!=pattern[j])

            {

            flag=0;

            break;

            }// end if

else

{

    flag=1;

}

        i++;

        }// end further check for

    } /// a match is found end if

}/// main for loop

 if(flag==0)

 printf("\n\t\t+++++++++++++++++++++++++++++++++++++++++++\n\t\t\t\tNo match found \n\t\t+++++++++++++++++++++++++++++++++++++++++++ \n");

else

  {

   printf("\n\t\t+++++++++++++++++++++++++++++++++++++++++++\n\t\t   pattern is present from location %d\n\t\t+++++++++++++++++++++++++++++++++++++++++++ \n",loc);

  }

getch();

}

+++++++++++++++++++++++++++++END C SOURCE CODE +++++++++++++++++

++++++++++++++++++C++ SOURCE CODE +++++++++++++++++++++++++++++++++

#include <iostream>

#include <conio.h>

using namespace std;

int main ()

{

char str[999],pattern[999];

int flag=0,loc;

cout<<"Enter the string \n";

cin.getline(str,999);

cout<<"Enter the string to find pattern\n";

cin.getline(pattern,999);

for(int i=0;str[i]!='\0';i++)

{ /// main for loop

    if(flag==1) break;

    if(str[i]==pattern[0])

    {/// a match is found

        i++;loc=i;

        flag=1;

        for(int j=1;pattern[j]!='\0';j++)

        {

            if(str[i]!=pattern[j])

            {

            flag=0;

            break;

            }// end if

else

{

    flag=1;

}

        i++;

        }// end further check for

    } /// a match is found end if

}/// main for loop

 if(flag==0)

 cout<<"\n\t\t+++++++++++++++++++++++++++++++++++++++++++\n\t\t\t\tNo match found \n\t\t+++++++++++++++++++++++++++++++++++++++++++ \n";

else

    cout<<"\n\t\t+++++++++++++++++++++++++++++++++++++++++++\n\t\t   pattern is present :from location "<<loc<<"\n\t\t+++++++++++++++++++++++++++++++++++++++++++ \n";

getch();

}

+++++++++++++++++++++++ END C++ SOURCE CODE +++++++++++++++++++++